Given Set \(M:\ 0,\ 1,\ 3,\ 4,\ 7\) and Set \(N:\ 1,\ 2,\ 3,\ 4,\ 5,\ 9\). Calculate the mean and mean absolute deviation for both sets. Then, answer the following questions.

How many data points in Set (M) are closer than one mean absolute deviation from the mean of Set (M) ?
How many data points in Set (M) are further than two mean absolute deviations from the mean of Set (M)?
Find the difference between the two means. How does this difference relate to the mean absolute deviation of each set? For example, is it the same as the mean absolute deviation, twice as much, half as much, etc?

Please help me I'll give the Brainliest

points are handed out whenever you post answers.

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if you're asking about your rank, it depends on having a certain number of points and a certain number of brainliest answers. for example, at the time of this writing, i have 44338 points out of 15000 needed for the next (nearly triple the requirement! ) but i only have 24 out of 50 required brainliest answers. this number decays, meaning after a certain amount of time (i think about a month), the total number of brainliest answers you've earned doesn't count toward this total. (i've been stuck at the same rank for a long

the lesson to learn here is that you shouldn't worry about points or rank. chances are, no matter how good an answer you may provide, your efforts will go mostly unnoticed unless you focus on the newest/most active questions that get posted.

1,918

step-by-step explanation:

problem:

f(x) = - 2/3x + 5; f(5/2)

substitute 5/2 in for x:

f(5/2) = -2/3(5/2) + 5

simplify the right side:

f(5/2) = -5/3 + 5

f(5/2) = 10/3

f(5/2) = 10/3

i hope this !