Mathematics, 04.09.2021 15:00 silvermansachs9189
E) Fill in "AT", "IN" or "ON":
My birthday is ... on the 30th of July. Last year I had a great day, I got up ..Olur
8 o'clock the morning and tidied the house. Then
the afternoon I went into
town with my friend to buy food for the party. The party started
7 o'clock
the evening and didn't stop until very late night!
the 31" of July I was
very tired, so I went to bed early the evening.
F) Fill in the spaces in the invitation with "IN", "ON" or "AT”,
I'm going to have a party! I hope you can come!!
It's going to start 5 o'clock the afternoon
the secong Saturday August. We're
going to have it in Tom's house on Wilton Avenue.
There's a big garden and we're going to have the party in
the garden
Did you know that my birthday is the eighth? But
as you can see, the party is going to be the tenth.
Why? Parties are better the weekend!
BIRTHDAY PRESENTS WELCOME ANYDAY
Answers: 2
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Asmall (but heavy) particle placed in a glass of water will follow a zigzag motion because the particle will bounce off of the water molecules it meets. this is called brownian motion. a physicist simulates this on a computer, by varying the distance a particle can travel (called the mean free length), on average, before it collides with a water molecule and assigning the change in motion to be one of 8 directions, each with a similar probability. by running the simulated particle (with the same mean free length) many times she determines that it should take 15 seconds, on average, for the particle to fall to the bottom, with a standard deviation of 1.5 seconds. next she lets a real particle fall through a glass of water and finds that it took 18 seconds. what does she conclude, and why?
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Refer to the table below if needed. second quadrant third quadrant fourth quadrant sin(1800- - cos(180° -) tan(180°-e) =- tane cot(1800-0) 10 it to solo 888 sin(180° +c) = - sine cos(180° +) =- cose tan(180° +c) = tane cot(180° +o) = cote sec(180° + c) = - seco csc(180° +2) = - csce sin(360° -) =- sine cos(360° -) = cose tan(360° - e) =- tane cot(360° -) = -cote sec(360° -) = seco csc(360° -) = csco sec(180° -) = csc(180° -) = csca 1991 given that sine = 3/5 and lies in quadrant ii, find the following value. tane
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E) Fill in "AT", "IN" or "ON":
My birthday is ... on the 30th of July. Last year I had a great da...
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