What is the solution of the equation 3(4b – 2) = –6 + 12b?

infinite number of solutions

Step-by-step explanation:

3(4b - 2) = - 6 + 12b ← distribute parenthesis on left side by 3

12b - 6 = 12b - 6

The expressions on both sides are the same

This indicates the equation has an infinite number of solutions

d. bc = 12 and ef = 16

step-by-step explanation:

we are given that δabc : δdef such that .

also, it is given that

so, from the options, we need that .

a.

b.

c.  

d.

as, we can see that only option d gives the same ratio as i.e. .

hence, the possible lengths are bc = 12 and ef = 16.

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐