Find k so the distance from (-1,1) to (2,k) is 5 WILL GIVE BRAINLISET

its 6

Step-by-step explanation:

1+5=6

k = -3

k =5

Step-by-step explanation:

\begin{gathered}d = \sqrt{(x_2-x_1)^2+(y_2-y_1)^2}\\d = 5\\(-1,1) =(x_1,y_1)\\(2,k)=(x_2,y_2)\\\end{gathered}

d=

(x

2

−x

1

)

2

+(y

2

−y

1

)

2

d=5

(−1,1)=(x

1

,y

1

)

(2,k)=(x

2

,y

2

)

\begin{gathered}5=\sqrt{\left(2-\left(-1\right)\right)^2+\left(k-1\right)^2}mathrm{Square\:both\:sides}:\quad 25=k^2-2k+10\\25=k^2-2k+10mathrm{Solve\:}\:25=k^2-2k+10:\\k^2-2k+10=25mathrm{Subtract\:}25\mathrm{\:from\:both\:sides}\\k^2-2k+10-25=25-25\\k^2-2k-15=0mathrm{Solve\:by\:factoring}mathrm{Factor\:}k^2-2k-15:\quad \left(k+3\right)\left(k-5\right)\\\mathrm{Solve\:}\:k+3=0:\quad k=-3\\\end{gathered}

5=

(2−(−1))

2

+(k−1)

2

Squarebothsides:25=k

2

−2k+10

25=k

2

−2k+10

Solve25=k

2

−2k+10:

k

2

−2k+10=25

Subtract25frombothsides

k

2

−2k+10−25=25−25

k

2

−2k−15=0

Solvebyfactoring

Factork

2

−2k−15:(k+3)(k−5)

Solvek+3=0:k=−3

\begin{gathered}\mathrm{Solve\:}\:k-5=0:\quad k=5k =5 , k=-3\end{gathered}

Solvek−5=0:k=5

k=5,k=−3

Step-by-step explanation:

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second option

step-by-step explanation:

the measures of a triangle equal 180. use that to find x.

2x+3x+4x=180

9x=180

9x/9=180/9

x=20

now you know x, you know angle a is 40°, angle b is 60°, angle c is 80°.

because angle a is 40°, the first option doesn't work.

because angle b is 60°, the second option does work.

when you add angle a and b, you get 100°. complementary means it equals 90°, so the third option doesn't work.

when you add angle a and c, you get 120°, which is not 100.