Given T5 = 96 and T8 = 768 of a geometric progression. Find the first term, a and the common ratio, r. I'll mark u as the brainliest, do help me!​​

Of the given geometric sequence, the first term a is 6 and its common ratio r is 2.

Step-by-step explanation:

Recall that the direct formula of a geometric sequence is given by:

Where Tₙ is the nth term, a is the initial term, and r is the common ratio.

We are given that the fifth term T₅ = 96 and the eighth term T₈ = 768. In other words:

Substitute and simplify:

We can rewrite the second equation as:

Substitute:

Hence:

So, the common ratio r is two.

Using the first equation, we can solve for the initial term:

In conclusion, of the given geometric sequence, the first term a is 6 and its common ratio r is 2.

1. 2

2. 8

3. 9

step-by-step explanation:

lol can i have brainliest, i spent hours trying to figure these mind boggling math questions out

x = -2

y = 848

step-by-step explanation:

plug in the numbers