8(sin⁶p + cos⁶p) = 5+3cos4p​

this is going to be alot i am very sorry. i had to put it like that im sorry

Step-by-step explanation:

As

a

3

+

b

3

=

(

a

+

b

)

(

a

2

+

b

2

−

a

b

)

8

(

sin

6

P

+

cos

6

P

)

=

8

(

sin

2

P

+

cos

2

P

)

(

sin

4

P

+

cos

4

P

−

sin

2

P

cos

2

P

)

=

8

(

sin

4

P

+

cos

4

P

+

2

sin

2

P

cos

2

P

−

3

sin

2

P

cos

2

P

)

=

8

(

(

sin

2

P

+

cos

2

P

)

2

−

3

sin

2

P

cos

2

P

)

=

8

(

1

−

3

4

(

4

sin

2

P

cos

2

P

)

)

=

8

−

6

sin

2

2

P

=

8

−

6

(

1

−

cos

2

2

P

)

=

2

+

6

cos

2

2

P

As

cos

4

P

=

2

cos

2

2

P

−

1

, we have

cos

2

2

P

=

1

+

cos

4

P

2

Hence,  

8

(

sin

6

P

+

cos

6

P

)

=

2

+

6

×

1

+

cos

4

P

2

=

2

+

6

2

+

3

cos

4

P

=

5

+

3

cos

4

P

on friday there were 15 birds

in problems involving proportions, we can use cross products to test whether two ratios are equal and form a proportion. to find the cross products of a proportion, we multiply the outer terms, called the extremes, and the middle terms, called the means.

hope it