If BTS had 9/7/5/6=45/42 can you simplify 45/42

< coa = 150 ( given)

as ba and bc are tangents

so oc and oa is perpendicular to cb and ab respectively because in circle normal passes through centre

so in quadrilateral oabc

< coa + < oab + < ocb + < abc = 360

150 +90+90 + < abc = 360

330 + < abc = 360

< abc = 360 -330 = 30

so < abc = 30

⭐dhruv⭐

step-by-step explanation:

in which figure is point g a centroid

probability for j is 1/4

while

a is 1/6

i think it would be 42cm