The length of a rectangle is four times its width. If the perimeter of the rectangle is 50 in, find its area

The perimeter of a rectangle is the sum of all of it’s sides. Since a rectangle has 2 lengths of the same size and two widths of the same size, the perimeter is length + length + width + width, or 2(length) + 2(width), or, to make it shorter, 2l + 2w.

Since the length of the rectangle (l) in this scenario is really 4w, we can replace those, and get 2(4w) + 2w, and since we know the total is 50, we can say 2(4w) + 2w = 50.

Using the distributive property, we get 8w + 2w = 50, and 10w = 50, or w = 5. Since the length is 4w, the length is 4*5 = 20.

To find the area, you multiply length and width to get 5 * 20 = 100 sq meters.

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hello :

70y^8 + 30y^6 = 2 ( 35 y^8 + 15y^6)

the lenght is : 35 y^8

the width is : 15y^6

f(x) = y

f(-3) = -5

step-by-step explanation: