A math textbook has 900 pages. The teacher had covered 312 pages in the first form and 289 pages in the second form. The teacher needs to cover the entire textbook in the third form. How many pages of the textbook had the teacher covered in the first and second form altogether? And how many more pages left does the teacher need to cover in the third form?

312 + 289 = 601 in total of 1st and 2nd form

3rd from page = 900-601 = 299.

Vote me

Step-by-step explanation:

The teacher needs to cover 299 pages in the third form. And the teacher already covered 601 pages in the first and second.

42%

step-by-step explanation:

we know,

total people = 60

total males = 25

percentage of males

= 25/60 × 100

= 25/6 × 10

= 25/3 × 5

= 125 / 3

= 41.

rounding of = 42%

happy to

pls mark as brainliest

the polynomial is a perfect square trinomial of the form a^2-2ab+b^2:

option a. true

step-by-step explanation:

9x^2-12x+4

comparing with the form a^2-2ab+b^2

1.) a^2=9x^2

solving for a: square root both sides of the equation:

sqrt(a^2)=sqrt(9x^2)

a=sqrt(9) sqrt(x^2)

a=3x

2.) b^2=4

solving for b: square root both sides of the equation:

sqrt(b^2)=sqrt(4)

b=2

to be a perfet square trinomial 2ab must be equal to 12x. let's check:

2ab = 2 (3x) (2)

2ab = 12x

correct