Let ABC be a right triangle at A(AB a. Prove: AH=MN.
b. Prove: angle B = angle ANM.
c. Let AD be the median of triangle ABC. Prove: AD is perpendicular to MN.

i think is 3 and 6. this took me 10 min to think.hope to and hope that my answer is brainliest.(follow me )

answer: the price of one pound cabbage = $ 0.8

the point (10,8) represents that the cost of 10 pounds cabbage is $ 8

step-by-step explanation:

since, here is a proportional relation between the number of pounds of cabbage (x) and the price in dollars (y).

therefore, we can write,

⇒ y = k x

where k is the constant of proportionality.

now, point (5,4) is in the line.

thus, it will satisfies the above equation of line.

⇒ 4 = 5 k

⇒ k = 0.8

thus, the equation of the line is,

y = 0.8 x

a) for x = 1,

y = 0.8

therefore, the cost of one pound of cabbage is 0.8 dollars.

b) in the below graph (10,8) represents that the cost of 10 pounds of cabbage is 8 dollars.

the answer would be 150 books

step-by-step explanation:

if you divide 300 by 2 you will get 150

exactly you go it

step-by-step explanation: