(4-xy)(5x-3y)-(x+y)(x-3y)

20x-12y-5x²y+3xy²-x²+2xy+3y²

Step-by-step explanation:

(4-xy)(5x-3y)-(x+y)(x-3y)

20x-12y-5x²y+3xy²-(x+y)(x-3y)

20x-12y-5x²y+3xy²-x²+2xy+3y²

for finding the midpoint of any given 2 pair of points simply add the respective x coordinates with other x coordinate and the y coordinate with other y coordinate and divide them by 2

in your question it will be :

(3+1)/2 for the x coordinate of mid point i.e 2

[8+(-4)]/2 for the y coordinate of midpoint i.e 2

so coordinates of mid point of points (3,8) and (1,-4) will be (2,2)

i think it's ф or x=6,-6

step-by-step explanation:

-x^2=-36

x^2=-36

ф

or

if you mean by : -(x^2)=-36

it'll be: x^2=36

x=6,x=-6

hope it'll ! have a good day!

you for asking!