I need help with #21 ASAP.. I need to get it done…. Show step by step please help me with it.. I need to get it done tonight it is passed due

1) 2/5

2) zero=0/1

3) zero=0/2

4) -4/5

5) undefined=3/0

place r′ so that qr′ is parallel to the tangent.

now we get that ∠r′py=∠pr′q, where y is on the tangent, on the opposite side of p from x.

also, because of the symmetry, ∠r′py=∠qpx.

finally, note that no matter where we place r, as long as it's on the correct arc, we have ∠prq=∠pr′q.

stringing all these equalities together, we end up with ∠prq=∠qpx.

this picture will show how its going to look like.

hope this by jack monhen