A classic physics problem states that if a projectile is shot vertically up into the air with an initial velocity of 177 feet per second from an initial height of 133 feet off the ground, then the height of the projectile, h, in feet, t seconds after it's shot is given by the equation:

h=−16t^2+177t+133

Find the two points in time when the object is 172 feet above the ground. Round your answers to the nearest hundredth of a second (two decimal places).

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step-by-step explanation:

let's solve your equation step-by-step.

24−3x=−27

step 1: simplify both sides of the equation.

24−3x=−27

24+−3x=−27

−3x+24=−27

step 2: subtract 24 from both sides.

−3x+24−24=−27−24

−3x=−51

step 3: divide both sides by -3.

−3x

−3

=

−51

−3

x=17

answer:

x=17

step-by-step explanation:

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according to the triangle sum theorem, all the angles in a triangle must add up to 180 degrees. if we know one angle is already 90, we do 180-90=90. the other 2 angles must add up to 90, exactly.

step-by-step explanation:

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