find the exact coordinates of X on segment JK that is 1/3 the distance from j to k. J (-1,4) K(5,-3)​

To find the point that's one-third of the distance from (–4,1) to the other endpoint, (8,7): Replace x1 with –4, x2 with 8, y1 with 1, y2 with 7, and k with 1/3. Subtract the values in the inner parentheses. Do the multiplication and then add the results to get the coordinates

intensity of the vector is v= √37 ≈ 6.08 units and make angle ∡α ≈ 9.46° with east direction

step-by-step explanation:

required vector is consists of the two componentsvx= 2+4=6 units   and vy= 1 unit and vx ⊥ vywe will use pythagorian theorem to find intensity of the vector vv∧2 = vx∧2 + vy∧2 => v = √vx∧2 + vy∧2 = √6∧2 + 1∧2 = √36+1 = √37 ≈ 6.08 unitsthe angle ∡α between vector and east direction we wil find with tanαtanα = 1/6 => α = arc tanα = arc 1/6 => α ≈ 9.46°

hope this

the answer is 844

step-by-step explanation:

it is 844 because if you add 836.50 + 7.5 you will get 844