The period of a compound pendulum is given by T=2π√(h²+k²/gh) express k in terms of T, h and g​

Complete the square to determine the minimum or maximum value of the function defined by the expression. x2 − 12x − 2 a) maximum value at 38 b) minimum value at 38 c) maximum value at −38 d) minimum value at −38

What is [tex] {7}^{98 + \sqrt{4} } - 3 \times (64 \div 2 + 4 - 36) \times a = a + 36[/tex]?

Solve the equation for x.3(6x - 1) = 12 i've tried doing the math and i can't find out what i'm doing wrong