Four coins are tossed. What is the probability of at least one tail?​

Step-by-step explanation:

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93.75%

This type of problem you have to REVERSE the question...

"at least one tail" is all possibilities EXCEPT "all heads"...

so your answer is 100% - P(4 heads)

P(4 heads) = (1/2)^4 = .0625

1 - .0625 = .9375

Step-by-step explanation:

answer:

the position of equilibrium will shift to the left.

step-by-step explanation:

the general equation for the dissociation of a weak base is

b + h₂o   ⇌   bh⁺ + oh⁻

according to le châtelier's principle, when a stress is applied to a system at equilibrium, the system will respond in a way that tends to relieve the stress.

if you apply a stress by adding more bh⁺ or oh⁻,   the system will respond by moving in a direction that gets rid of the added ions.

the position of equilibrium will shift to the left, forming more of the undissociated base.

michael scott & dwight schrute

step-by-step explanation:

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