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The diagram shows the structure of a molecule of sulfur dioxide. The ratio of oxygen atoms in sulfur dioxide is always the same. How many oxygen atoms (O) are there when there are 6 sulfur atoms (S)? Explain how you got your answer.

Sulphur (iv) Oxide (SO₂)

In a single SO₂ Molecule... There's 2 oxygen atoms.

Now

If there a 6 molecules of SO₂

Quick Math

6 x 2 = 12.

Simply put...

THERE'S 12 OXYGEN ATOMS WHEN THERE'S 6 SULPHUR ATOMS.

Another way to look at it is

In SO₂

The ratio of Sulphur to Oxygen is 1:2

Meaning that the amount of Oxygen is double that of sulphur

Since the question stated "When there are 6 sulphur atoms"

It simply means that there's gonna be 12 Oxygen atoms.

logv3(x+2)=1

rewrite in exponential form:

logb(x) = y is equal to b^y =x

b = 3, y = 1

now solve for x:

3^1 = x+2)

x = 3-2

x = 1

see the picture for the graph.