Form simultaneous equations and solved using only one method. In the two digit number the unit digit is thrice the tens digit if 36 is added to the number the digits interchange their place find the number

48

Step-by-step explanation:

48

Let the tens digit be x.

Hence, the units digit will be 2x

Number =10×(x)+(2x)=12x

When 36 is added to the number, the new number formed =12x+36

As the digits are reversed, we can also write the new number as 10×(2x)+x=21x

Hence,

12x+36=10×(2x)+x

⇒12x+36=21x

⇒21x−12x=36

⇒9x=36

⇒x=4

Hence, the original number =12x=12×4=48

4

Step-by-step explanation:

12x+36=10{2x}+x

=12x+36=21x

=21x-12x-36

=9x=36

=4

one that is bigger than 3 1/2

i am unable to solve this problem

step-by-step explanation: