H(x) = 1/x+2 and k(x) = 3x - 4 h[k(x)] =

A.(3x - 4)/(x+2)
B. 1/(4x - 2)
C. 1/(3x - 2)

 = 1/ (3x-2)

Step-by-step explanation:

H(x) = 1/(x+2)

k(x) = 3x - 4

h[k(x)] =  place the function k(x) in for x in the function h(x)

           = 1/(3x-4 +2)

Combine like terms

           = 1/ (3x-2)

Hey there! I'm happy to help!

What we need to do is take the value of k(x) which is 3x-4 and plug it into the function h(x).

This is because our x in the function h[k(x)] is k(x), so we will substitute that value for x in that formula and that will give us our answer.

H[(k(x)]=1/(3x-4+2)

And combine like terms

H[(k(x)]=1/(3x-2)

So, our answer is C. 1/(3x-2)

Have a wonderful day and keep on learning! :D

10cm

step-by-step explanation:

ik

hello from mrbilldoesmath!

answer:

x - 3

discussion:

x^2 - 9 = (x-3) (x+3)   so

(x^2-9)/ (x + 3) = x-3

you,

mrb