Write the cubes of 5 natural numbers which are of the form 3n + 1 (eg.4,7,10…)and verify the following "The cube of a natural number of the form 3n + 1 is a natural number of the
Same form
in when divided by 3 it leaves the remainder 1'

yes it is true

Step-by-step explanation:

write the first five elements then write their cubes then write the cubes in the same form

for eg:

4³=16= 3×5+1= 3n+1

7³=49=3×16 +1= 3n + 1

and so on till the fifth element...

w'x is 0.

hope it

question 1: step-by-step explanation:

1/4 of 84 = 84÷4= 21