How high is a tree that cast a26ft shadow at the same time a 6ft post casts a shadow which is 11ft long

ft

Step-by-step explanation:

Let the height of the tree equal x. Shadows are proportional to the height of an object, so we can write a proportion where to numerators are the object and the denominators are the shadow:

Now, to solve for x, we can cross-multiply:

11x = 6*26

11x = 156

x =  

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet