Find the area of the triangle with the vertices A (3, -5), B (-2, -7) and C (18, 1) such that A, B and C are collinear.

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Step-by-step explanation:

Many authors do not recognize three points on a line as forming a triangle. This is because its area is zero. (The "base" is the length of the line segment; the "height" is the width of the line (zero).)

goog may be able to you find that answer

x = -3

y = -18

step-by-step explanation:

to solve by substitution, substitute one variable and solve for the other. then substitute again to find the remaining variable.

x-1/3(3x-9) = -3 since y=3x-9 substittute y.

x-1/3(3x-9)=-3

x + x +3 = -3

2x+3=-3

2x+3-3= -3-3

2x=-6

x=-3

substitute again into y=3x-9

y=3(-3)-9

y=-9-9

y=-18