Two jets leave an airbase at the same time and travel in opposite directions, One jet travels 71mi/h faster than the other. If two jets are 7014 miles apart after 6 hours what is the speed of each jet?

jet1 = 549 mi/h

jet2 = 620 mi/h

x= jet1

x + 71 = jet2

6 hours

6 * x

6 * x + 71

6x + 6x + 426 = 7014

12x = 7014 - 426

12x = 6588

x = 6588/12

x= 549

x + 71 = 620

wyzant

step-by-stp

the correct answer is the section c

160

step-by-step explanation:

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