In a mathematical competition, there are 2021 participants. Gold, silver, and bronze medals are awarded to the winners as follows: the number of silver medals is at least twice the number of gold medals: i the number of bronze medals is at least twice the number of silver medals: ii) the number of all medals is not more than 40% of the number of participants. The competition director wants to maximize the number of gold medals to be awarded based on the given conditions. In this case what is the maximum number of bronze medals that can be awarded?

Here we have some given restrictions that affect the number of medals, using these, we want to find the maximum number of bronze medals that can be awarded.

We will find that:

The maximum number of bronze medals that can be awarded is 535

Now let's see how we can get that.

Let's define the variables:

G = number of gold medals.

S = number of silver medals.

B = number of bronze medals.

Now we can see what information we have.

There are 2021 participants.

The number of silver medals is at least twice the number of gold medals.

S ≥ 2*G

The number of bronze medals is at least twice the number of silver medals:

B ≥ 2*S.

The number of all medals is not more than 40% of the number of participants.

The total number of medals is (G + S + B)

40% of the total number of participants is:

(40%/100%)*2021 = 0.4*2021 = 808.4

Then we have:

G + S + B ≤ 808.4

We can rewrite the above inequality as:

G + S + B ≤ 808.

Then we have 3 inequalities:

S ≥ 2*G

B ≥ 2*S

G + S + B ≤ 808

Now we want to maximize the number of gold medals.

This means that the total number of medals should be exactly 808 (the maximum number of total medals) so we have:

G + S + B = 808.

Also, if we want to maximize the number of gold medals, then we need to minimize the number of silver medals and the number of bronze medals, such that we get:

S = 2*G

B = 2*S

Now we have 3 equations:

G + S + B = 808

S = 2*G

B = 2*S

Replacing the third equation in the first one, we get:

G + S + 2*S = 808

G + 3*S = 808

Now we can replace:

S = 2*G

in the above equation to get:

G + 3*(2*G) = 808

G + 6*G = 808

7*G = 808 =

G = 808/7 = 115.43

But we can have 0.43 of a gold medal, so we need to round down to the next whole number:

G = 115

Now, with this restriction, we want to find the maximum number of bronze medals.

This means that we need to minimize the number of silver medals, so we use:

S = 2*G = 2*115 = 230

And the number of bronze medals will be such that:

B + G + S  = 880

B + 115 + 230 = 880

B = 880 - 115 - 230 = 535

The maximum number of bronze medals that can be awarded is 535

If you want to learn more, you can read:

16.9 times 2.85

step-by-step explanation:

m∠cdf = 43° , m∠gdf = 114°, m∠gde = 23°, m∠edh = 23° , m∠cdh = 157°

step-by-step explanation:

since, it is given that de bisects the angle gdh ⇒ de divides the angle gdh into two equal angles.

⇒ m∠gde = m∠edh

⇒ 8·x   - 1 = 6·x + 5

⇒ x = 3

so, m∠gde = 8·x - 1 = 23°

and m∠edh = 23°

now, it is given ∠cde is an straight angle so, m∠cde = 180°

⇒ m∠cdf + m∠fdg + m∠gde = 180°

⇒ 43° + m∠fdg + 23° = 180°

⇒ m∠fdg = 114°

again, m∠cde = m∠cdh + m∠edh = 180°

m∠cdh + 23° = 180°

⇒ m∠cdh = 157°