Find the equation of the parabola that has a vertex at (2,0) and a y-intercept of (0,12). Question 19 options:

A)

y = 3(x + 2)2

B)

y = (x – 2)2

C)

y = (x + 2)2

D)

y = 3(x – 2)2

D

Step-by-step explanation:

standard form would be 3x^2-12x+12

vertex form y=3(x-2)^2

step-by-step explanation:

y = | -2(-2) |     →     y = | 4 |     →     y = 4       ⇒   (-2, 4)

y = | -2(-1) |     →     y = | 2 |     →       y =   2       ⇒   (-1, 2)    

y = | -2(0) |     →     y = | 0 |     →       y = 0         ⇒   (0, 0)

y = | -2(1) |   c →     y = | -2 |     →     y =   2         ⇒   (1, 2)    

y = | -2(2) |     →     y = | - 4 |     →     y =   4         ⇒   (2, 4)