Mathematics, 12.08.2021 21:30 kenrick99

In a first-class lever like a see-saw, the force (F) varies inversely with distance (d) from the pivot point, or fulcrum. On one side of the see-saw, a force of 12 N was applied at a distance of 3 m from the fulcrum. In order to balance the see-saw, how much force must be placed 4 meters from the fulcrum on the other side? Type answer as a whole number (no decimals, no units).

In a first-class lever like a see-saw, the force (F) varies inversely with distance (d) from the pi

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In a first-class lever like a see-saw, the force (F) varies inversely with distance (d) from the piv...