1. Determine the set of each of the following equations for 0° ≤ x 360° or 0° ≤ t ≤ 360° a) sin 2 x°= 1/2√2

2. find all the solution in the interval 0° ≤ z ≤ 360° of the following equation
sin 3 z = - 0,42

Please help Me​

a).

since sine is in the 2nd quadrant, other angle = 180° - x:

we must make two rotations since it's a double angle:

divide each angle by 2:

Answer = {x: x = 22.5°, 67.5°, 112.5°, 157.5°, 247.5, 337.5°}

b).

since ans is negative, we take the quadrants of cosine and tangent:

we make three rotations:

answer is {z : z = 128.3°, 171.7°, 231.7°, 291.7°, 351.7°}

answer: i think it's a

step-by-step explanation: