Help pls! I need the answer quickly and pls explain. thank you!

h = 6

Step-by-step explanation:

The given is the special right triangle with angle measures : 90-60-30

and the side lengths for the given angles are represented by :

2a-a-a

the side length that sees 60 degrees is represented by a (h in this case)

the area of a triangle is calculated by multiplying height and base and that is divided by 2

a*a/2 = 18 multiply both sides by 2

a^2 = 36 divide both sides by

a^2 = 36 find the roots for both sides

a = 6

since h sees angle measure 60 and is represented by a

h = 6

step-by-step explanation:

is their an equation anywhere i can take a   look at it and see if i am right.

1. when "a" is a root of a polynomial, (x -a) is a factor of it. for the three roots given, the factors of the desired polynomial are (x +2)(x -1/2)(x -3).

in order to make the leading coefficient be negative, we need to multiply this product by a negative number. any negative number will do, but we choose a small (magnitude) value that will eliminate the fraction: -2.

then

f(x) = -2(x +2)(x -1/2)(x -3) = -(x +2)(2x -1)(x -3)

= -(2x² +3x -2)(x -3)

= -(2x³ -3x² -11x +6)

f(x) = -2x³ +3x² +11x -6

2. a graph created by the desmos on-line graphing calculator is shown, and the zeros are highlighted.

3. as indicated in part 1, the multiplier of this equation can be anything and the zeros will remain the same. you want a negative leading coefficient, so the "anything" is restricted to any of the infinite number of numbers that will make that be the case.