You roll a cube which has the numbers 9, 10, 12, 15, 17, and 18 on it You then spin a spinner which has 4 sections. The letters on the spinner are H, K, F, and A. P(F and 17)​

Step-by-step explanation:

The fact that the numbers look random and the spinner also looks random doesn't matter. The only thing of importance in both cases is that all the numbers are different (and cannot be made by adding any two together) and all the letters are different

That means you have 6 numbers and 4 letters.

You have a 1/6 chance of throwing the 17

You have a 1/4 chance of spinning the F

P(F and 17) = 1/6 * 1/4 = 1/24

(2x + 16) + (x) = 180

step-by-step explanation:

given,

abcd is a quadrilateral inscribed in a circle

angle a is labeled x plus 16, (x + 16)

angle b is labeled x degrees, (x)

angle c is labeled 6x minus 4, (6x – 4)

angle d is labeled 2x plus 16, (2x + 16)

what equation can be used to solve for angle b?

we know that the sum of the opposite angles of a simple quadrilateral inscribed in a circle is 180 degrees.

angle b is opposite angle d

therefore, angle b + angle d = 180

(x) + (2x + 16) = 180 

same as (2x + 16) + (x) = 180

m∠5 + m∠3 = m∠1   is true.

m∠5 + m∠6 = 180 is true

m∠2 +m∠3 = m∠6   is true

m∠2 +m∠3 +m∠5 = 180   is true