Someone help pleasee

Step-by-step explanation:

g(x) = 3f(-2x)

     = 3*([-2x)² + (-2x) - 2)

    = 3 (4x² - 2x - 2)

   =   3 * (4x² - 4x  +2x - 2)        {Rewrite the middle term}

  = 3 *[ 4x(x - 1) + 2(x - 1)]

 = 3* [ (x -1) *(4x + 2)]

 = 3(x - 1)(4x + 2)

x - 1 = 0    ;   4x + 2 = 0

x = 1         ;      4x   = -2

                        x =

Roots:   x = 1 , (-1/2)

answer: the resulting cross section is a rectangle. solution: a plane parallel to the base of a triangular prism will intersect a cross section that is the same shape as its bases. so the cross section is a triangle.

step-by-step explanation:

the equation of the parallel line would be y = 2x + 9

step-by-step explanation:

to start we need to find the slope of the original line. we can do that by looking at the coefficient of x, which is 2

since the slope of the original line is 2 and parallel lines have the same slope, we know the new line will also have 2 slope. now we can use that along with the point given in point-slope form to get the find equation.

y - y1 = m(x - x1)

y - 5 = 2(x + 2)

y - 5 = 2x + 4

y = 2x + 9