Please help me with these​

19x = -38

x = -2

(-2,5)

Step-by-step explanation:

3(5x + 2y = 0)

2(2x - 3y = -19)

First step is to simplify the equations by using the distributive property.

3(5x + 2y = 0)

distribute the 3 by multiplying 3 by everything inside of the parenthesis

3 * 5x = 15x

3 * 2y = 6y

3 * 0 = 0

first equation simplified: 15x + 6y = 0

2(2x - 3y = -19)

distribute the 2 by multiplying 2 by everything inside of the parenthesis

2*2x = 4x

2 * -3y = -6y

2 * -19 = -38

second equation simplified: 4x - 6y = -38

We acquire the two equations

15x + 6y = 0

4x - 6y = -38

Notice how there are two 6ys, one is negative and the other is positive. When this happens we can add the two equations together and solve for x. We can do this because the two 6ys will cancel out and we will be left with one variable. when there is only 1 variable you can solve it.

So add the two equations

+ 15x + 6y = 0

4x - 6y = -38

19x = -38

now solve for x

divide both sides by 19

19x/19 = -38/19

x = -2

Now we need to find the value of y.

To do so simply plug in the value of x into one of the equations and solve for y

4x - 6y = -38

x = -2

4(-2) - 6y = -38

multiply 4 and -2

-8 - 6y = -38

add 8 to both sides

-6y = -30

divide both sides by -6

y = 5

The solution to the system is (-2,5)

x= -1

y= 2.5

Step-by-step explanation:

15x+6y=0

4x-6y=-19

19x = -19

x=-1

-15+6y = 0

6y=15

y=2.50