Given three consecutive even integers whose sum is 54, find the largest of the three integers.

Step-by-step explanation:

16, 18, 20

(n) + n+2 + n+4

We only took even numbers

20

Step-by-step explanation:

Let the least integer = x. The three consecutive even integers can be denoted as:

x , x + 2 , x + 4

Set the equation:

(x) + (x + 2) + (x + 4) = 54

Simplify. Combine like terms:

(x + x + x) + (2 + 4) = 54

(3x) + (6) = 54

3x + 6 = 54

Isolate the variable, x. Note the equal sign, what you do to one side, you do to the other. Do the opposite of PEMDAS.

PEMDAS is the order of operation and stands for:

Parenthesis

Exponents (& Roots)

Multiplication

Division

Addition

Subtraction

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First, subtract 6 from both sides of the equation:

3x + 6 (-6) = 54 (-6)

3x = 54 - 6

3x = 48

Next, divide 3 from both sides of the equation:

(3x)/3 = (48)/3

x = 48/3

x = 16

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Next, find the largest of the three integers, which was denoted as x + 4:

x + 4

(16) + 4 = 20

20 is the largest integer.

Check:

x + (x + 2) + (x + 4) = 54

16 + (16 + 2) + (16 + 4) = 54

16 + 18 + 20 = 54

16 + 38 = 54

54 = 54 (True).

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you need more information to answer this question

step-by-step explanation:

6,250

step-by-step explanation:

to get the area, multiply 360 by 160.(57,600)

to find out how many bags of fertilizer it will take, first figure out how many square feet one bag can hold. divide 1000 by 8(125) to get the unit rate(how many square feet one pound of fertilizer can hold)and multiply it by 50(6250). if i haven't made a mistake, that is the answer.