Isabella saved $13,000 and bought a car that cost $11,675. The insurance for the car will cost $650 per year. How many full years will Isabella be able to pay for car insurance with her remaining savings?

isabella will be able to pay 2 full years of insurance with her remaining savings

Step-by-step explanation:

as we know isabella saved $13,000

the car cost $11,675 - so subtracting that from her total we will know that she has: $1,425 remaining

insurance for a year costs $650,

so we will divide her remaining sum by the yearly cost giving us -

1,425/650

= ‎‎‎2.19

this means that she will be able to pay for 2 full years of insurance with her remaining savings

hope this helped:)

Explanation:

x = number of years

Since it costs $650 a year for insurance, she will pay 650x dollars of insurance in total over those x years.

For example, if x = 4, then 650*x = 650*4 = 2600 dollars is paid in insurance.

The expression 650x is added onto the 11675 which is the cost of the car.

Overall, Isabella pays 650x+11675 dollars as the combined cost of the car itself and the insurance over those x years.

Set this equal to 13000 and solve for x

650x+11675 = 13000

650x = 13000 - 11675

650x = 1325

x = 1325/650

x = 2.03846 which is approximate

Rounding down to the nearest whole number gets us to x = 2

She will be able to afford 2 full years of insurance

Note that if x = 3, then,

650x+11675

650*3+11675

13625

Which is 625 dollars over her budget. This shows that she cannot have x = 3 or larger.

72 is the answer to this problem

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