Help please! thanks!
Find the length of AB
A. 2.89
B. 33.13
C. 378.63
D. 377.19

Explanation:

Segment AB is already given to be 19 miles long.

I'm assuming your teacher meant to ask about side BC, which is side 'a' since it's opposite angle A.

Use the law of cosines to find the missing side

a^2 = b^2 + c^2 - 2*b*c*cos(A)

a^2 = 12^2 + 19^2 - 2*12*19*cos(138)

a^2 = 843.874040417691

a = sqrt(843.874040417691)

a = 29.0495101579647

a = 29 when rounding to the nearest whole number

Side BC is roughly 29 miles long.

there are many solutions.

step-by-step explanation:

step 1: simplify both sides of the equation.

4x+6=4x^2+10x−4

step 2: subtract 4x^2+10x-4 from both sides.

4x+6−(4x^2+10x−4)=4x^2+10x−4−(4x^2+10x−4)

−4x^2−6x+10=0

step 3: factor left side of equation.

−2(2x+5)(x−1)=0

step 4: set factors equal to 0.

x=-5/2 or x=1

d) 30 units^2

area of rectangle = l × b

we know,

length = 10 unit

breadth = 3 unit

applying the formula,

= l × b

= 10 × 3

= 30 unit^2

happy to

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