If Quinn tosses a fair coin and then rolls a fair number cube labeled 1 through 6 what is the probability of tossing heads followed by rolling a number less than 5?

1/3

Step-by-step explanation:

Coin has heads or tails {H,T}

P(heads) =heads/ total = 1/2

Die has 6 possible outcomes {1,2,3,4,5,6}

There are 4 numbers less than 5 {1,2,3,4}

P(less than 5) = numbers less than 5/ total = 4/6 = 2/3

The events are independent so we multiply the probabilities

P(heads, less than 5) = 1/2 * 2/3 = 1/3

answer: the correct one is a

step-by-step explanation:

answer: all of the odd numbers were opened

the first person was the one that was opening all of the lockers. since one is odd, this causes all of the odd number lockers to be opened in the end.