BRAINLIEST Which equation could be solved using this application of the quadratic formula? A.
x2 + 1 = 2x − 3
B.
x2 – 2x − 1 = 3
C.
x2 + 2x − 1 = 3
D.
x2 + 2x − 1 = -3

Quadratic formula:  [ +/-   is   ± ]    

You can find the value of a, b, c  -->  ax² + bx + c = 0  

 Since this is not simplified, you can find a, b, c:

a = 1

b = 2

c = -4

A.)  x² + 1 = 2x − 3   Make the equation into ax² + bx + c = 0. Subtract 2x on both sides, and add 3 on both sides to set the equation equal to 0

x² + 1 - 2x + 3 = 2x - 2x - 3 + 3

x² - 2x + 4 = 0      

a = 1

b = -2

c = 4    This is not the answer because b = 2 not -2, and c = -4 not 4

B.) x² - 2x − 1 = 3     Subtract 3 on both sides to set the equation = 0

x² - 2x - 4 = 0

a = 1

b = -2

c = -4      This is not the answer because b = 2 not -2

C. x² + 2x - 1 = 3    Subtract 3 on both sides to set the equation = 0

x² + 2x - 4 = 0

a = 1

b = 2

c = -4    This is your answer

D. x² + 2x - 1 = -3      Add 3 on both sides to set the equation = 0

x² + 2x + 2 = 0

a = 1

b = 2

c = 2       This is not the answer because c = -4 not 2

well the 1 and -1 are always after the 0 and the 0 is inthe middle. s thats what i would guess. but i dont know what a slope of 2 is sorry

step-by-step explanation:

d

step-by-step explanation:

hello and welcome!

so, when we see the words "proportional" along with a table, we need to know that we're looking numbers that divide by the same thing.

looking at this table, we simply have to do a trial and error, and divide to see which numbers have the same quotient. if you look at choice a & c, they both have equal quotients for three of the numbers, with one exception, so those can't be the answer. looking at b, there is no similarity, so that can't be it. then, we see d; if you divide all the numbers in the table, you'll see that they all divide by two, which is a proportional relationship, and our answer!

also, always remember that the x will always be the number that goes into y, and somewhere behind this table, is a formula. for this specific table, the formula would be:

since our x-value is being divided by two to get the y-value. and if they were to ask for more numbers in the series, this is the formula you would use to find them.