Sociologists say that 90% of married women claim that their husband's mother is the biggest bone of contention in their marriages (sex and money are lower-rated areas of contention). Suppose that six married women are having coffee together one morning. Find the following probabilities. (For each answer, enter a number. Round your answers to three decimal places.)

The number of women out of 12 selected dislike their mother-in-law is a random variable that can be represented by X. Then X is a Binomial distribution with

P( dislike their mother-in-law) p = 0.90

n= 12

Therefore, the probability distribution of X is P(x)= nCxp^x(1-p^(n-x) x=0,1,. ... ,12

1) P(all of them dislike their mother-in-law)= P(X=12) = (12C12)(0.90)^12(0.10)^0

= 0.2824

2) P(none of them dislike their mother-in-law) =P( X=0) = 12C0(0.90)^0(0.10)^12

=1x10^(-12)

3) P(at least ten of them dislike their mother-in-law)= P(X>=1)=1-P(X=0)

=1-1x10^(-12)=0.9999999999999

4)P(no more than two of them dislike their mother-in-law) =P( X<=2)

=p(X=0)+P(X=1)+P(X=2)= 5.45x10^(-9)

step-by-step explanation:

i believe its "c" because all of the other options include a but it could be d because there is a way of financing with cash at certain places but its uncommon.