2π(a-r)(a+r)+4 = 52π
Can someone solve this pleas

a²-r²= 22

Step-by-step explanation:

2π(a-r)(a+r)+4 = 52π

=> 2π(a²-r²)+4= 52π

=> (a²-r²)+4 = 52π/2π

=> (a²-r²)+4 = 26

=> (a²-r²)= 26-4

=> a²-r²= 22

the smallest possible measurement of the width is 14 feet

step-by-step explanation:

let's assume length of parallelogram is 'l'

width of parallelogram is 'w'

the perimeter of a parallelogram must be no less than 40 feet

so, we get

we are given

length of parallelogram is 6 feet

so,

l=6

we can plug it

now, we can solve for w

subtract both sides by 12

divide both sides by 2

and we get

so,

the smallest possible measurement of the width is 14 feet