If x=4(3-y)(2^2-1), what is the value of y in terms of x?

hello there...

x = 4(3-y)(4-1)

x =( 12 - 4y )(3)

x = 36 - 12y

-12y = 36+x

y = (36+x)/(-12)

y = -(36+x)/12 or y = (-36-x)/12

AND WE ARE DONE <3

y=3-x/12

Step-by-step explanation:

x=4(3-y)(2^2-1)

x=4(3-y)(4-1)

x=3*4(3-y)

x=12(3-y)

x/12=3-y

y=3-x/12

18

step-by-step explanation:

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answer rather than having to add and subtract the measurements of the semi-circle, notice that the semicircle to the left of ad is actually identical in area to the blank semicircle-shaped space to the left of bc. so if we transferred the red semicircle into the blank space, we would end up with a square of side length 24 cm. the area of a square is s^2 = 24^2 = 676 cm^2.

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