To prepare for the town's race, Andrew runs around a rectangular field. The dimensions of the field are 450 feet by 225 feet. How many times must Andrew run around the field in order to run 12 miles? One mile is 5,280
fect.
Round the answer to one decimal place if necessary?

46.9 times

Step-by-step explanation:

First, we can calculate how many feet it takes to run around the field. To find the perimeter of a rectangle, we can use the formula

2* length + 2 * width. With the length being 450 and the width being 225 here, we can say that

2*450 + 2 * 225 = 1350 feet

Therefore, Andrew runs 1350 feet each time he runs around the field. Next, we need to figure out how much 1350 feet goes into 12 miles as we want to find how many times Andrew runs around the field to get to 12 miles. This can be represented by

12 miles/1350 feet

One thing that we can do here is multiply the fraction by 1 to keep it the same. Because 1 mile = 5280 feet, we can say that

1 mile/5280 feet = 1 = 5280 feet/1 mile. Therefore, it would be safe to multiply

12 miles/1350 feet by 1 = 5280 feet/1 mile. Note that feet is on the bottom in the first fraction (12 miles/1350 feet) and on the top in the second (5280 feet/1 mile) so they will cancel out. Similarly, miles are on top in the first and bottom in the second. We then have

12 miles/1350 feet * 5280 feet/1 mile =63360/1350 ≈ 46.9

x=-2

infinite number of lines, so there is an infinite number of equations.

step-by-step explanation:

there are an infinite number of line that passes through the point (-2,5)

x=-2   is one line that passes through the point

y = 5 is another line that passes through the point

(these two lines are perpendicular to each other).

since the number of   numbers are infinite and the slope is the ratio of two numbers,(change in y over change in x) we can have an infinite number of slopes.     our only condition is that it passes through the point (-2,5)