A sequence starts 0, 5, ... Give a rule the sequence could follow and the next 3 terms for that rule.

Give a different rule the sequence could follow and the next 3 terms for that rule.

0, 5, 10, 15, 20

0, 5, 40, 405, 5,120

Step-by-step explanation:

One rule can be "add 5 to the previous term to get the next term."

0, 5, 10, 15, 20

Second rule:

For each term number 1, 2, 3, ..., n,

each term = 5(n - 1)^n

0, 5, 40, 405, 5,120

The next three terms for the rule Tn = a + (n-1)d will be 10,15 and 20

The next three terms for rule 5(n-1)ⁿ will be 40, 405 and 5120.

Sequences are numbers arranged in a specific pattern.

Given the sequence 0, 5...

This sequence can be an arithmetic sequence with nth term expressed as:

a is the first term = 0

n is the number of terms

d is the common difference = 5 - 0  5

If n = 3

T3 = 0 + (3-1)*5

T3 = 2 * 5

T3 = 10

If n = 4

T4 = 0 + (4-1)*5

T4 = 3 * 5

T4 = 15

If n = 5

T5 = 0 + (5-1)*5

T5 = 4 * 5

T5 = 20

Hence the next three terms for the rule will be 10,15 and 20

Also, we can also use the recursive rule f(n) = 5(n-1)ⁿ

If n = 3

f(3) = 5(3-1)³

f(3) = 5(2)³

f(3) = 5 * 8

f(3) = 40

If n = 4

f(4) = 5(4-1)⁴

f(4) = 5(3)⁴

f(4) = 5 * 81

f(4) = 405

If n = 5

f(5) = 5(5-1)⁵

f(5) = 5(4)⁵

f(5) = 5 * 81

f(5) = 1024 * 5

f(5) = 5120

Hence the next three terms for the rule will be 40, 405, and 5120.

Learn more here:

the correct answer is x/3+10≥32

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