A card is drawn from a well shuffled deck of 52 cards what is the probability of drawing an ace or a six

8/52

Step-by-step explanation:

The first thing to do is write it out;

How many aces are in a deck and how many sixes?

There are 4 of each so, 4+4 = 8 therefore our beginning ratio will be;

8/52 cards are going to be an ace or a six.

(n^3 - n)

= n(n-1)(n+1)

since it is divisible by 3 and 2 ,because it is a multiple 3 consecutive number

if, n-1 is odd then n+1 is also odd, then it is a multiple of 9

but if, n-1 is even then n+1 is also even, then it is a multiple of 4

so, largest multiple = max(9*2, 4*3) = max(18, 12) = 18

maybe - definition of supplementary angles. im not sure. sorry

step-by-step explanation: