Sons Find the values of a and b in the rhombus, Solve for the value of c, it ca tb.
3b+4, (5a-5)
A
Question Progress
(14a +20)
13b-9
A5
OB.4.7
Oct
0,63
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2
30
13'5 Sunny

D

Step-by-step explanation:

The sides of a rhombus are congruent , then

13b - 9 = 3b + 4 ( subtract 3b from both sides )

10b - 9 = 4 ( add 9 to both sides )

10b = 13 ( divide both sides by 10 )

b = 1.3

The diagonals are perpendicular bisectors of each other , then

14a + 20 = 90 ( subtract 20 from both sides )

14a = 70 ( divide both sides by 14 )

a = 5

Thus c = a + b = 5 + 1.3 = 6.3 → D

when studying polynomials, you often hear the terms zeros, roots, factors and x x the multiplicity of a zero is important because it tells us how the graph of the let's look at the graph of a function that has the same zeros

step-by-step explanation:

infinitely many solutions

step-by-step explanation:

we have been given the equation;

2(2x + 3) = -4 + 2(2x + 5)

we need to determine the value of x.

2(2x + 3), we expand this expression to obtain 4x + 6

similarly 2(2x + 5) will become 4x + 10

now we have;

4x + 6 = -4 + 4x + 10

4x + 6 = 4x + 10 - 4

4x + 6 = 4x + 6

the expression on the left hand side is identical to the one on the right hand side. therefore, we are looking at just a single straight line whose equation is;

y = 4x + 6

consequently, we shall have infinitely many solutions