a gift wrapping store has 8 shapes of boxes, types of wrapping paper, and 12 different bows. How many different gift-wrapping options are available at this store?

This sum is related to fundamental principal of counting which states that if one thing is happen in m different ways and other thing happen in n ways, Then both thing will happen in mn ways. We shall use its generalised form.

In given sum, Number of shapes of boxes=8

Number of types of wrapping papers=14

Number of different bows=12

As gift wrapping includes three items Therefore by fundamental principal of counting, number of different gift wrapping option =8×14×12= 1344

Step-by-step explanation:

768

Step-by-step explanation:

8 boxes* 8 paper * 12 bows

768 different combinations

(x3 + 6x2 + 2x - 6) • (x - 1)

step-by-step explanation:

polynomial long division :

3.2     polynomial long division

dividing :   x4+5x3-4x2-8x+6

                              ("dividend")

by         :     x-1     ("divisor")

dividend     x4   +   5x3   -   4x2   -   8x   +   6

- divisor   * x3     x4   -   x3            

remainder         6x3   -   4x2   -   8x   +   6

- divisor   * 6x2         6x3   -   6x2        

remainder             2x2   -   8x   +   6

- divisor   * 2x1             2x2   -   2x    

remainder               -   6x   +   6

- divisor   * -6x0               -   6x   +   6

remainder                     0

quotient :   x3+6x2+2x-6   remainder:   0

no ,sorry if you needed it but you can ask and try to see if any one will anwser ,

step-by-step explanation:

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