I need help ASAP!! Please explain how to solve the problem

area of base = pi x radius^2 = (ill use 3.14 as pi)

3.14 x 7^2 = 153.86 in^2

height = 12

circunference of base = 2 x pi x radius or pi x diameter (diameter = 2 x radius) = 3.14 x 14 = 43.96 in

surface area = perimeter of base x height (lateral area) + 2 x area of base

= 43.96 x 12 = 527.52 + 2(153.86) = 835.24

hope that answers your question

(be careful, i generally use 3.14 as pi, but if your question says to use other forms as pi, then just replace pi as what the question asks, ive given you the formulas on how to calculate area and circumf., so i hope it should be easier...)

all but the second one

step-by-step explanation:

cuz that one goes over 180

mark brainliest

∠1≅∠2 by the alternate exterior angles theorem.

step-by-step explanation:

given, a ∥ b and ∠1 ≅ ∠3 .we have to prove that e ∥ f

we know that ∠1≅∠3 and that a || b because they are given. we see that by the alternate exterior angles theorem. therefore, ∠2≅∠3 by the transitive property. so, we can conclude that e || f by the converse alternate exterior angles theorem.

we have to fill the missing statement.

transitivity property states that if a = b and b = c, then a = c.

now, given ∠1≅∠3 and by transitivity property ∠2≅∠3 .

hence, to apply transitivity property one angle must be common which is not in result after applying this property which is ∠1.

the only options in which ∠1 is present are ∠1 and ∠2, ∠1 and ∠4

∠1 and ∠4 is not possible ∵ after applying transitivity we didn't get ∠4.

hence, the missing statement is ∠1≅∠2.

so, ∠1≅∠2 by the alternate exterior angles theorem.