How many times more ?

1.3

Step-by-step explanation:

bc for each time x increases by 1, it multiplies by 1.3

i cant think of any other way to explain it

but   i hope this helped :D

1.3 times

Step-by-step explanation:

f(x)= 68 (1.3) ^x

it, means each year, the expected number of squirrels is 1.3 times, the number the year before.

x=0 so, f(0)=68

New x=1, so f(1)= 68(1.3)¹

= 68 × 1.3

f (1)= f(0) × 1.3

So, 1.3 times

OAmalOHopeO

what graph

step-by-step explanation:

step-by-step explanation: so we look at the formula un = a + (n-1)d

un is the amount of seats

n is the nth term aka row number

a is the original sequence/row number

d is the difference between each term

so in this a=22 d=6 and n can remain as n because we are simply formjng a rule

lets put these in the equation

un=22+(n-1)(6)

this is your answer to part a

however

lets double check that this is correct, we'll try putting it into the second term

un=a+(n-1)d

u2=22+(2-1)(6)

u2=22+6

u2=28

as the question said the second row has 28 seats so now we know the formula we made is correct.

as for part b

un=a+(n-1)

its asking us to find a row with 100 seats.

remember un was the amount of seata so all we do is substitute this in.

un=100 a=22 d=6

un=a+(n-1)d

100=22+(n-1)(6)

so now we simplify to find n which is the row number.

100-22=22+(n-1)(6)-22

78=(n-1)(6)

78/6=(n-1)(6)/6

13=n-1

13+1=n-1+1

14=n

so now we know that in the 14th row there is 100 seats.

hope this and that you understood! its my first time using the app or anyone out on here : p its also me to revise so a bunch! ask more questions if you dont understand ☺