SAQ 5.2 1. Find the value of x, given that x + 1, 2x and 2x + 3 are consecutive terms of an arithmetic progression.

2. The sum of the 3rd and 7th terms of an A. P. is 38, and the 9th term is 37. Find the A. P.

3. If x + 1, 2x - 1 and x + 5 are in A. P., find the value of x.

4. Insert 4 arithmetic means between -12 and 13

center (1,3) with radius 6

step-by-step explanation:

we must complete the square to find the center and radius of the circle.

first make sure the x and y squared terms have 1 as their coefficients. we also make sure x and y terms together.

we now create space between the x and y terms with parenthesis.

we complete the square by taking the middle terms -2x and the -6y - divide each and square them.

we add the squares to both sides.

simplify.

and write the quadratics in factored form.

the center is (h,k) or (1,3). the radius is the square root of 36 which is 6.

step-by-step explanation:

the correct answer is b.

this is because an open circle means < or > & since the line goes left it is < -3.

the next one has a filled circle so it can only be ≥ or ≤ and since the line goes right from 1 it is ≥ 1

hope that

the easiest way to do these would be to solve the equations. if you can solve the equation than you can solve these problems.