Weekly wages at a certain factory are normally distributed with a mean of
$400 and a standard deviation of $50.
Find the probability that a worker
selected at random makes between
$350 and $400.

0.34134

Step-by-step explanation:

in other to solve for this question we would be using the z score formula

z = (x - μ) / σ

x = raw score

μ = mean

σ = standard deviation

the question tells us to find the probability that a worker selected at random makes between $350 and $400

let x1 = 350 and x2= 400 with the mean μ = 400 and standard deviation σ = $50.

z1 = (x1 - μ) / σ = (350-400) / 50 = -1

z2 = (x2 - μ) / σ = (400 - 400) / 50 = (0/50) = 0

from tables, P(z <= -1) = 0.15866

P(z <= 0) = 0.5

then the probability would give us, P(-1 ≤ z ≤ 0) =0.5 - 0.15866 =

0.34134

that explains that the probability that a worker selected at random makes between $350 and $400 = 0.34134

this linear equation would have just one solution.

step-by-step explanation:

the reason why this would have one solution is that it is an expression with just one variable. since that variable is not raised to a power, it will always have just one solution.

answer:   (s+1)(s+4)

step-by-step explanation:

factor s2+5s+4

s2+5s+4

=(s+1)(s+4)