Find the equation of the line which passes through the point (3,-2)and is perpendicular to the line 3x+2y-4=0

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y = 2/3 x - 4

Step-by-step explanation:

first rewrite the given equation in slope intercept form

3x+2y-4=0

2y=-3x+4

y = -3/2x + 2

the gradient of the perpendicular is -1/ the gradient of the normal

-1/(-3/2) = 2/3

so the equation looks like y = 2/3 x + c

putting in the point you are given you get

-2 = 2/3 * 3 + c

-2 = 2+c

c = -4

so the equation is y = 2/3 x - 4

pls thank and mark brainliest

Provided by Guathmaths

step-by-step explanation:

this is not a question

step-by-step explanation: 4 cause 2+2=4