Find the slope intercept form and the point slope (HELP) - the line perpendicular to 4x-7y=2 going through (-6,1)

1) slope intercept y= (-7/4)*x-19/2 2) point slope y-1= -7/4*(x+6)

Step-by-step explanation:

4x-7y=2

7y= 4x-2

y=(4/7)*x-2/7

To find the m2 (the number near x, it is called slope) for searched the slope intercept

use the formula for perpendicular lines

m1*m2=-1

m1= 4/7

m2= -1/ (4/7)= -7/4.

The slope intercept must look like y=m2*x+b

Use the coordinates of given point of the searched line (-6,1)  and m2= -7/4.

1= (-7/4) *(-6) +b

b= -19/2

So slope intercept is y= (-7/4)*x-19/2

Point slope formula is y-y1= m2(x-x1)  m2=-7/4. x1=-6 y1=1

y-1= -7/4(x+6)

the entire expression should be subtracted from 30. to subtract the quantity, distribute the negative sign, which changes the signs on the terms. so, the –2 changes to positive and gets added to 30 instead of subtracted from it.

hope this ! ^w^

sorry can't

step-by-step explanation:

i googled though and something came up but it was in science langueage not common english sooo